Homework Answers
Solution:
Given in the question
p= 0.02
UCLp can be calculated as = p + 3*sqrt(p*(1-p)/n)) = 0.02 +
3*(0.02*0.98/100) = 0.02+ 0.0420 = 0.0620
LCLp can be calculated as = p + 3*sqrt(p*(1-p)/n)) = 0.02 +
3*(0.02*0.98/100) = 0.02- 0.0420 = -0.022
but defect rate can not be in -ve or less than 0 so LCLp = 0
SO UCLp = 0.0620 and LCLp = 0
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i
dont have any more informafoon to add besides rhis pther example of
tne type of problem
0405/20 1:47 Homework: Chapter S6 Homework Score: 0 of 1 pt + 2 of 7 (4 complete) Problem 6s.16 HW Score: 46.43%, 3.25 of The defect rate for your product has historically been about 1.00%. For a sample size of 400, the upper and lower 3-sigma control chart limits are: Question Help UCL = enter your response as a number between 0 and...
I need help getting the UCL and LCL
ePage-61919.20 x)" course Home hrome-Do Homework-dylan Boest 을 Secure | https://www.mathxl.com/Student/PlayerHomework.aspx?homeworkid-493290252&qu Operations Management Sat Homework: Chapter S6 Homework Score: 0 of 1 pt 3 of 11 (2 complete) HW Score: 0%, 0 of 11 X Problem 6s.16 EQuestion Help The defect rate for your product has historically been about 1.00%. For a sample size of 500, the upper and lower 3-sigma control chart limits are: UCLp-(enter your response as a number between...
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