Question

Calculate the number of pounds of Co, released into the atmosphere when a 24.0 gallon tank of gasoline is burned in an automobile engine. Assume that gasoline is primarily octane, CHg, and that the density of gasoline is 0.692 g.mL-1. This assumption ignores additives. Also, assume complete combustion. Useful conversion factors: 1 gallon = 3.785 L 1 kg = 2.204 lb number of pounds of Co, released:

Answer 1

Auswer. 2Cq Hi8 +2502 man of c8 H182 > 16 Co + 18420 volume (mclx density lgmul 1 gallon = 3.785 L 20-0 gallon = 3.78524 28-0 gallon 1 gallon 90.84 L :. man of Cq HIS = 90.86x103 mL X 0.692 gmly 62.86 x103g moles of CGH18 = man = 62-86x103 g .so -ssl.41 m) molarmeens legmort 2 mol cq H18 giver 16 mel cez SSkal mel eq 418 gives 16 mol Cer X SS141 mol Cq his 2 mol cq HIS = 44 11.3 malce mass of co= malex melarmare = 4411-3 mdx regner/ = 194,097.9879 - 194 kg Now 1 kg = 2.20916 1.194 kg - 2-20416X199 kg = 427.79 Lb laugwal