Question

pts] Danche Mikhail studied the use of prenatal only of prenatal care among low-income African American women. She found percent of these women had adequate prenatal care. Let us assume that bate prenatal care la accume that for a population of similar low income African American women, 51% had ade had adequate prenatal care. If 200 women from this population are drawn at dom. What is the probability that more than 40% will have not received adequate prenatal care

Answer 1

Solution

Given that,

p = 0.51

1 - p = 1 - 0.51 = 0.49

n = 200

$\mu$_{$\hat p$} = p = 0.51

$\sigma$_{$\hat p$} =  $\sqrt$[p ( 1 - p ) / n] =  $\sqrt$ [(0.51 * 0.49) / 200 ] = 0.0353

P( $\hat p$ < 0.40)

= P[( $\hat p$ - $\mu$ _{$\hat p$} ) / $\sigma$ _{$\hat p$} < (0.40 - 0.51) / 200 ]

= P(z < -3.12)

Using z table,

= 0.0009