Question

6. In the titration of 90.0 mL of 0.150 M ethylamine, C2H5NH2, with 0.100 M HCl, find the pH at each of the following point in the titration. C2H5NH2 has a Ko value of 6.4 x 104. After 60mL of HCl has been added

Answer 1

Ansneer -buiven -Nolary of co s4 g 90- o mL O.100M oler Hany acia): GomL Volume taKen s0, Amount milrity (H)xvolumu (mi) 90 0 mL 13 S mM 13.5 milli'mles r SA taken inihag inuilaly amount (N) volvme Cm muteriy 60 mL 0.100 M 6o mM 6.0 mllmy frrm Salts As Know, auds heatts uuth kar to e this uitratton heact Lakss ae dauing and to salt re SA 6/w WB + Salt of weak base. SA Trlelly inatyCs-6) 13-5 mmit C.o mm mmol G-Omme 7-5 mmit

the rmpetwn o hracton Wak base e Hana a uhich are ane bas e 7-5mmd 6.0 mm) As neak and alnd G mix- uHer drlution uni PtsAalt an eguahon Such a Hen- fru des om- HLays elb aleh Cbase pon au lsted as we Know pH L pM= 14-PoH Sow 169117 CB ase pM14-prs 6 mmit 14 Know We K6 3.1938
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bH14 3-1938 s L C 0 8 3.1938 14 O 8 u-31936 --0.09 69) 14-3.193& 8- 3 19 38+o .09 69) 14.0 9691~ 3.1여38 lo.903) 10 G03) mixt s Hence