Homework Answers
let
m1 = 20 g
v1x = 3*cos(37) = 2.396 m/s
m2 = 30 g
v2x = -2 m/s
let v is the velocity of both objects after the
collision.
Apply conservation of momentum in x-direction,
m1*v1x + m2*v2x = (m1 + m2)*v
==> v = (m1*v1x + m2*v2x)/(m1 + m2)
= (20*2.396 + 30*(-2))/(20 + 30)
= -0.242 m/s
so, speed = 0.242 m/s <<<<<<<---------------Answer
direction : towards left
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