A very nice test is that N is a Fibonacci number if and only if 5 N^2 + 4 or 5N^2 – 4 is a square number.
code
=========================================================================
// C++ program to check if x is a perfect square
#include <iostream>
#include <math.h>
using namespace std;
// A utility function that returns true if x is perfect
square
bool isPerfectSquare(int x)
{
int s = sqrt(x);
return (s*s == x);
}
// Returns true if n is a Fibinacci Number, else false
bool isFibonacci(int number)
{
// n is Fibinacci if one of 5*n*n + 4 or 5*n*n - 4 or both
// is a perferct square
return isPerfectSquare(5*number*number + 4) ||
isPerfectSquare(5*number*number - 4);
}
// A utility function to test above functions
int main()
{
int n;
cout<<"Enter the inputs :\n";
for(int i=0;i<=100;i++)
{
bool result=true;
cout<<"Input: ";
cin>>n;
if(n>0)
{
if(isFibonacci(n) == result)
{
cout<<n << " is fibonacci number\n";
}
else
{
cout<<n <<" is not a fibonacci number\n";
}
}
else
{
cout<<n<<" Goodbye \n";
break;
}
}
return 0;
}
===================================================================================
Hope this will help.
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