What volume of an aqueous 0.25 M solution of HCl is needed to completely neutralize an aqueous solution of NaOH that has a pH of 12.5 and a volume of 200 mL?
pH = 12.5
pH + pOH = 14
pOH = 1.5
[OH-] = 10^-pOH
[OH-] = 0.0316 M
Volume = 200 mL
millimoles of NaOH = millimoles of HCl
0.0316 x 200 = 0.25 x V
V = 25.3 mL
volume of HCl = 25.3 mL
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