Homework Answers
1) py+ r+= 180
py+ r= 22
py r+= 19
py r= 191
Total=412
Recombination frequency= number of recombinant progeny/ total number of progeny X 100
The recombinants are py+ r and py r+
Recombination frequency= 22 +19/412= 0.09951 X 100= 9.951
Total proportion of py alleles= (19+191)= 210
b)
Expected ratio for this dihybrid cross is 8:8:8:8= 1:1:1:1 ratio
Degree of freedom= No of phenotypic characters-1= 4-1=3
The genes are not linked.
Chi square value at p=0.05 for df=3 is 12.838.
The (O-E) values are not identical in all columns.
Hence, the genes are not linked, as law of independent assortment is applicable (due to probability being more than 12.838).
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