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The following are the impulse resposes of continuous-time LTI systems. Determine whether is causal and/or stable. Justify yor answers. cos2f (b) h(t)= e-Ha(2-t)

I'm pretty sure (b) and (c) are noncausal, but I don't know exactly why. I know in a y(t)=x(t)-x(blank) , you set the t=0 and if the x(blank) is negative, it's causal, and if it's positive, it's noncausal. However, I don't know how the e^{exponent} factors into this or why (c) is noncausal even though plugging in t=0 gives u(-1) ; I know in this case, you're supposed to set t= 1,2,3,-1,-2,-3 to reveal the noncausal value, but wouldn't doing that to others make any problem reveal a noncausal value?

Thank you.

engineering   Electrical-Engineering   
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Answer #1

A System chayacterised by ts ht) said to he Cauwai hetho for tco and stable if flhm]d t < It411 , ststemu causal み 1141 t41 e eJo system iu not stabl 4(2-t ) to for t<2 systemu non-causal bscaux htto fo 2. -み system & stable (B1B0)

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