The genes A and B are 25 cMs apart. If the dominant alleles are in trans...
The genes A and B are 25 cMs apart. If the dominant alleles are in trans in a dihybrid, the expected frequency of the ab gametes would be:
Answer is .125, but please explain very detailed how they got that answer!
Homework Answers
Answer: 12.5
The two genes are 25 cMs apart, so there is only a 25% chance of recombination (crossing over) between the genes. The dominant alleles (A and B) are in trans, so that means they are on the same different DNA strands (homologous chromosome). Allele A and b present on one chromosome and a and B on the other chromosome
Since crossing over occurs 25% of the time, then gametes from those events would be AB and ab and would represent 25% of the total resulting gametes. The AB & ab gamets would be in equal proportion, so the ab gametes would be 12.5% of them
The remaining 75% would be Ab and aB in equal proportion,
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