How to write this query in Formal Relational Query Languages?
SELECT M.Name, M.Email
FROM Manager AS M, ManagerCertificate AS MC
WHERE M.ID = MC.ManagerID
GROUP BY M.Name
HAVING count distinct (MC.CertificateID) = 2;
RESULT1 ← Manager ⨝ ID= ManagerID ManagerCertificate
RESULT2 ← π Manager.Name,
Manager.Email(Manager.Name ℑ Count
Distinct(CertificateID=2)(RESULT1))
Frist we have performed a Join operation on Manager and ManagerCertificate and stored it into a temporary table named RESULT1.
From the RESULT1 we are performing Project operation with a group by functiion which is represented by ℑ in relational algebra
<grouping attributes> ℑ <function list> (R)
How to write this query in Formal Relational Query Languages? SELECT M.Name, M.Email FROM Manager AS...
Problem 3 [40 points, Formal Query Languages]| Consider the following relational schema to represent information about suppliers S, parts P, and projects J, S#, P#, and J# are primary keys for S, P, and J respectively. For a tuple of SPJ, a particular supplier supplies a specific part to a specific project in the specified quantity S(S#, SNAME, STATUS, CITY) P(P#, PNAME, COLOR, WEIGHT, CITY) J(J#, JNAME,CITY) SPJ(S# P# J#, QTY) Write queries for the following requests in specified languages....
Please clear and direct answer Consider the following SQL query and related relations SELECT P.Name FROM Players P, Games G WHERE P.Id = G.PlayerId AND P.Game = 'Football' AND G.Season ='2019' where: Players (Id, Name, Game) Games (PlayerId, GameCode, Season) Translate the above SQL query to a relational algebra expression. Draw the Query tree for above relational algebra expression in part (a).
1 - Which of the following allows you to create subtotals in the output from a SELECT statement? Group of answer choices _ SUBTOTAL _ ORDER BY _ HAVING _ GROUP BY 2 - A query includes grouping done using the AVG, SUM, COUNT, MIN, or MAX function. Which SQL keyword is used to select rows after this grouping has been done? Group of answer choices _ WHERE _ DISTINCT _ HAVING _ LIKE 3 - Which of the following...
1- Consider the following SQL query and related relations SELECT P.Name FROM Players P, Games G WHERE P.Id = G.PlayerId AND P.Game = 'Football' AND G.Season ='2019' where: Players (Id, Name, Game) Games (PlayerId, GameCode, Season) A- Translate the above SQL query to a relational algebra expression. B- Draw the Query tree for above relational algebra expression in part (a). Note: Please no screenshot
MYSQL Applied Database I just want to make sure that the syntax looks okay for my database SQL statements, any help would be much appreciated: 1.A query that asks for customer star review for Tony Stark on Opportunity Detail. SELECT CONCAT (employee_first_name,' ',employee_last_name) AS employee_name, review_star_count, FROM customer_reviews, JOIN e employees ON employee_id =employee_id, WHERE employee_id=4 AND opportunity_id=1; 2.A query that shows how many orders Additional Dot Twain License, in an order totaling over $900. SELECT product_name, COUNT(o.OrderID) AS...
1. For each query, there are one or more things to do. Some of these queries use SQL constructs we haven't covered in class but that you should be able to figure out the meaning of. a. SELECT C.custid, C.companyname FROM Sales.Customers AS C LEFT OUTER JOIN Sales.Orders as O ON C.custid = O.custid WHERE O.orderid IS NULL Provide the result set generated by this query. One of the result rows should be (22, Customer DTDMN). What does this tell...
2. Specify the query using relational algebra Retrieve the name (first name, last name) of the employee who is either a manager or a supervisor. *Don't just copy and paste from another chegg post.
Please turn this join statement into a Sub-query. Select avg(baseball.sellingprice) as AverageSellingPrice, Suppliers.SupplierName From baseball, Suppliers where baseball.suppliercode = suppliers.suppliercode group by Suppliers.suppliername Having suppliers.suppliername = "logo goods"; Thank you
1. Select the correctly written query. SELECT ALL FROM CUSTOMERS WHERE 10243 IS CUSTOMERID PULL * FROM CUSTOMERS WHERE CUSTOMERID = 10243 GET LIST FROM CUSTOMERS SELECT * FROM CUSTOMERS WHERE CUSTOMERID = 10243 2. The GROUP BY clause can be used in place of a JOIN clause in a SQL query? True False 3. The number of join conditions is always equal to the number of tables being joined _____ one. Plus Divided by Times Minus
How do I combine these 2 queries to produce something like
this
QUERY 1
SELECT hotel.country, time.year, time.month,
COUNT(booking.room_id) as booked
FROM booking
LEFT JOIN room on room.room_id = booking.room_id
LEFT JOIN hotel on room.hotel_id = hotel.hotel_id
LEFT JOIN time on booking.time_id = time.time_id
GROUP BY hotel.country, time.year, time.month
ORDER by hotel.country, time.year, time.month
QUERY 2
SELECT hotel.country, time.year, time.month,
COUNT(checkout.room_id) as checkedout
FROM checkout
LEFT JOIN room on room.room_id = checkout.room_id
LEFT JOIN hotel on room.hotel_id = hotel.hotel_id
LEFT...