here,
mass , m = 2.9 kg
radius , r = 29 cm = 0.29 m
angular speed , w = 1400 rpm
w = 146.5 rad/s
the moment of inertia , I = 0.5 * m * r^2
I = 0.5 * 2.9 * 0.29^2 = 0.12 kg.m^2
the angular momentum , L = I * w
L = 0.12 * 146.5 kg.m^2 /s
L = 17.86 kg.m^2/s
the angular momentum is 17.86 kg.m^2/s
What is the angular momentum of a 2.9-kg uniform cylindrical grinding wheel of radius 29 cm...
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