| observed frequencey, O | expected proportion | expected frequency,E | (O-E)²/E | ||
| 83 | 0.301 | 82.78 | 0.001 | ||
| 49 | 0.176 | 48.40 | 0.007 | ||
| 32 | 0.125 | 34.38 | 0.164 | ||
| 22 | 0.097 | 26.68 | 0.819 | ||
| 25 | 0.079 | 21.73 | 0.494 | ||
| 18 | 0.067 | 18.43 | 0.010 | ||
| 13 | 0.058 | 15.95 | 0.546 | ||
| 17 | 0.051 | 14.025 | 0.631 | ||
| 16 | 0.046 | 12.65 | 0.887 |
chi square test statistic,X² = Σ(O-E)²/E =
3.559
level of significance, α= 0.05
Degree of freedom=k-1= 9 -
1 = 8
P value = 0.8946 [ excel function:
=chisq.dist.rt(test-stat,df) ]
Decision: P value >α , Do not reject Ho
so, sample is according to law
......................
THANKS
revert back for doubt
please upvote
Bentood's law first nou zero numher in a snolom distrihatin of it's " 56 PlXex)] 0.301...
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