Question

given the following circuit

v= 66 volts

R1= 5 ohms

R2 = 14 ohms

R3 = 8 ohms

R4 =6 ohms

R5=8 ohms

R6= 9 ohms

R7= 7 ohms

R8= 8 ohms

what is the total power dissipated by all the resisitors excluding 1,3, and 6 answer in watts.

Question 3 1.2 pts 3) Given the following circuit with V = 46 Volts, R2 = 5 Ohms, R2 = 14 Ohms, R3 = 8 Ohms, R = 6 Ohms, Rs - 8 Ohms, R - 9 Ohms, R, - 7 Ohms, and Rg - 8 Ohms, what is the total powe dissipated by all the resistors excluding resistors 1, 3, and 6? Answer in Watts. ww

Answer 1

Solution- Given data:- R = 52 R₂ = 14.2 R3 = 82 ; Rq = 6.2 R5=82 R6=98; Rq = 72 ; R8 = 88 V=66 volts IR I-I, RA Apply Kirchhoff's loup law in loop I YI, IR, + I, R2 + I,R3 +I Rg = V Put values I(R+R8) + IV (R2 +R3) - V 1(5+8) +(14 + 8) =V R7 I-I, 131 +221, = V 07 I = V-221; ---(1) Apply Kirchhoft's loop law in loop (1-1) (R+RE+RE+R+) - I, (R2+R3)=0 Put values (I-I) (6+8+9+7) – 1, (1478) =0 or (I-1)30 – 221, -0 og 301 - 301, -22 1, =0 Rg I or 52 I, = 30 I put value 52 T, = 30 V-221, 1 from ean (11 676 I = 300 - 660 1 13 336 : 1336 I = 30V 07 I = 30 v 1336 NOTE:- you provide two values for v, in image V= 46 volts and In typed value v=66 volts i'm solving for both for V = 46 volts | for V=66 volts I, - 30.66 or I = 1.482 A peut meacu I, - 30*46 or I, = 1.033A put menco I = 66-22(1.482) or I = 2.57A I = 46–22 (1.033) or I = 1:49A 13 lower dissipated by all resistores other than 1,386. Power dissipated by all resistors other the I 1,3 & 6 resiston. e-IR + (1-16)(R4 +R9+R7)+I+Rg Put values P=1,2R2+(1-11)2(R4+R5+R7) +22R8 +11.79-1.033) (6+8+7)+(1.798 P= (1-4821 (14+(2-57-1-482)2(6+817)+(2-57728 Answer P= 108.35 watts put values pe 52-60 watts or P = 52.61 watts