Question

For the following circuit, assume that R₁ = 1 ohm, R₂ = 2 ohms, R₃ = 8 ohms, and R₄ = 4 ohms. Also assume that V₁ = 50 volts and V₂ = 100 volts. Find the current through each of the resistors and the power dissipated through all of the resistors. (Hint: You’ll need to use Kirchoff’s Loop and Junction Rule)

Vi R2 R3 R4 NV

Answer 1

kindly rate

Applying KVL to loop A -50 = 9 I_A - 2 I_B 1 Applying KVL to loop B 100 = -2 I_A + 6 I_B 2. On solving, I_A = -2A and I_B = 16 A current through, R_1 rightarrow I_1 = I_A = -2A, R_2 rightarrow I_2 = I_B - I_A = 16-(-2) = 18 A R_3 rightarrow I_3 = I_A = -2A & R_4 rightwardsdoublearrow I_4 = I_B = 16 A power dissipated in resistor P_R1 = I^2_1 R_1 = (-2) ^2 times 1 = 2W P_R2 = I^2_2 R_2 = (18) ^2 times 2 = 648W P_R3 = I^2_3 R_3 = (-2) ^2 times 8 = 32W P_R4 = I^2_4 R_4 = (16) ^2 times 4 = 1024 W