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Consider a circuit with three resistors (R1 = 40.5 ohms, R2 = 54.8 ohms, and R3...

Consider a circuit with three resistors (R1 = 40.5 ohms, R2 = 54.8 ohms, and R3 = 30.8 ohms) connected to a 12.5 V battery as follows: R1 and R2 are connected in parallel. This combination is then connected in series to R3. Find the power dissipated in R1. Calculate the answer in watts (W) and rounded to three significant figures.

please explain.

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Answer #1

The power dissipatedin Ri is V. (12.5V) = 3.86w =-=- 3.86 W 40.5 Ω

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