Question

The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, VB, and VC). The resistor values are: R1=2 Ohms, R2=R3=8 Ohms, and the battery voltages are VA=25 V, VB=15 V, and VC=20 V. When the circuit is connected, what will be the power dissipated by R3?

0.75 W

1.25 W

2.67 W

4.2 W

5.5 W

Vc + R1 + VA VB R2 R3

Answer 1

Rz and R paralled, Requ 3 are in Req=42 ve VAT VBS TVC Es, current will R How through VA B "A Lim Req Apply Kirchhof's rule - i R, tvet VB ti ti heq = VA i(6) 25-15-20 z 1 = - 0 -1.67. Amp 6

R Rear w i til inz R So, current sime, both parallel resislame have the same value current will be equally distributed Current through R3 power dissipated = i²R = 0.697x 8 — - 0.835 Amp 2 be =5.57 Watt .

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