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The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, V8, and V). The resi
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5.5 W

Vc + R & Rp in parallel R2 R3 R. VA R2 + R3 A Rz .8 x 8 4r 8+8 then R R in seria V Ri & So, leg R+R = 2 +4 - 6 r hey -VA v V-Iz Iz t 1.67 = I = I 1.67 = 0.83 A 1) at o) N/A is dissipated by Rj Non, Power 2 = (0.83) P la 6² R₂ = 3 5.56 w = 3 5.5 W Aug

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