The following code of the program is explained with comments. Please let me know if you have any doubts regarding the code.
Code:
#include <stdio.h>
typedef int Table[100][100];
/* print_diagonal(T,n)
* Given a Table T, which will have n rows and n columns, print all of the
* entries on the main diagonal of T ( that is, entries whose row number and
* column number are equal). Remember to print a newline at the end. */
void print_diagonal(Table T,int n)
{
// This variable is used to keep track of index of T
int i=0;
// Iterating over the Table T
for(i=0;i<n;i++)
{
// printing the element on the main diagonal which is element at index T[i][i]
printf("%d ",T[i][i]);
}
// Printing the new line
printf("\n");
}
// This is the main function
int main()
{
// These three Tables are the inputs that are used to test the above function
Table T1 = { {10, 10, 2019},
{11, 14, 2019},
{111, 116, 225} };
Table T2 = { {1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16} };
Table T3 = { {1, 2, 3, 4, 5, 6, 7, 8, 9},
{10, 11, 12, 13, 14, 15, 16, 17, 18},
{19, 20, 21, 22, 23, 24, 25, 26, 27},
{28, 29, 30, 31, 32, 33, 34, 35, 36},
{37, 38, 39, 40, 41, 42, 43, 44, 45},
{46, 47, 48, 49, 50, 51, 52, 53, 54},
{55, 56, 57, 58, 59, 60, 61, 62, 63},
{64, 65, 66, 67, 68, 69, 70, 71, 72},
{73, 74, 75, 76, 77, 78, 79, 80, 81}};
// Calling the function print_diagonal with above inputs
print_diagonal(T1, 3);
print_diagonal(T2, 4);
print_diagonal(T3, 9);
return 0;
}
Sample Output:

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