Question

Consider the syntactically correct C code below, which is missing a function copy_positive.


#include <stdio.h>

 /* copy_positive(A, Aout, size)
  * Given an array A, which will have the provided size, copy all positive
  * (non-negative/non-zero) elements of A into the provided output array Aout.
  * Return the size of the resulting array. */
 /* (your code from below would be placed here) */

 void print_array(int arr[], int n){
     for( int i = 0; i < n; i++ )
     printf("%d ", arr[i]);
 printf("\n");
 }
 int main(){
     int A1[] = {0, 9, -1, 0, 6, 10, 17};
     int A2[] = {11, 1, 0, -5};
     int B[100]; int b_size;
     b_size = copy_positive(A1,B,7);
     print_array(B, b_size);
     b_size = copy_positive(A2,B,4);
     print_array(B, b_size);
     return 0;
 }

Write a definition of the function copy_positive (including the function signature). For full marks, your implementation should work correctly on all input values, not just the ones above.

Answer 1

#include <stdio.h>

 /* copy_positive(A, Aout, size)
  * Given an array A, which will have the provided size, copy all positive
  * (non-negative/non-zero) elements of A into the provided output array Aout.
  * Return the size of the resulting array. */
 /* (your code from below would be placed here) */
int copy_positive(int A[], int Aout[], int size){
    int count = 0;
    for(int i = 0;i<size;i++){
        if(A[i]>0){
            Aout[count] = A[i];
            count += 1;
        }
    }   
    return count;
}

void print_array(int arr[], int n){
     for( int i = 0; i < n; i++ )
         printf("%d ", arr[i]);
    printf("\n");
 }
 
 int main(){
     int A1[] = {0, 9, -1, 0, 6, 10, 17};
     int A2[] = {11, 1, 0, -5};
     int B[100]; int b_size;
     b_size = copy_positive(A1,B,7);
     print_array(B, b_size);
     b_size = copy_positive(A2,B,4);
     print_array(B, b_size);
     return 0;
 }