Question

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Average length to an ATG Please put all of your code for this problem in a file called lengthTOATG.py Let's assume that we have a long DNA sequence in which each symbol is random and equally likely to be an A, C, T, or G. We'd like to determine the average number of symbols until we see the first occurrence of a start codon "ATG" Once you've written a function to compute this, you'll do the same thing to find the average number of symbols until we see the first occurrence of the codon "AAA" Surprisingly, the average for "ATG" and the average for "AAA" are not the same! We'll break this task up into a few parts lengthToATG() First, write a function called lengthTOATG( ) that takes no input, generates a random letter from·A", "T", "C", or "G", and then if the last three letters generated are ATG", it returns the total number of symbols that were generated. Otherwise, it repeats the process by generating a next random letter Recall that in order to generate things at random, you simply include the line... import randon " "T", 叱· "6") to generate a random symbol from the list t , , , . at the top of your file. Then, you can use random. choice("A", Clearly, you'll need to have a loop to keep generating symbols untl we see the pattern 'ATG". Since we don't know in advance how many symbols wll need to be generated before we see this pattern, a while loop is the right choice

Answer 1

import random


def lengthToATG():
    count = 0
    seq = ''
    string = 'ACTG'
    while True:
        count += 1
        seq += string[random.randint(0, len(string)-1)]
        if seq.endswith('ATG'):
            break
    return count


def meanToATG(trials):
    total = 0
    for i in range(trials):
        total += lengthToATG()
    return total/trials


print(meanToATG(100))

1.6 Process finished with e xit code 0