The figure below shows the speed of a person's body as he does a chin-up. Assume the motion is vertical and the mass of the person's body is 57.4 kg. Determine the force exerted by the chin-up bar on his body at the following times.
(a) t = 0
N
(b) t = 0.5 s
N
(c) t = 1.1 s
N
(d) t = 1.6 s.
N
Homework Answers
a) v=0 hence a=0 and F= 0
b) slope ,a= 14/0.5 = 28 cm/s2
a= .28 m/s2
F=ma=16.072 N
c) v is const, a=0 hence F =0
d) a= 0 .0667 m/s2
F= ma = 3.826 N
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