Question

use C++ to write the following program.

4. Larger Than n In a program, write a function that accepts three arguments: an array, the size of the array, and a number n. Assume that the array contains integers. The function should display all of the numbers in the array that are greater than the numbern.

needs to ask the user for n

The user must put in those 5 values, probably using a for loop.

NOTE: You can assume the number of values to be entered is 5.

My attempted program below: (not correct, but just a basis)

Answer 1

#include<iostream>

using namespace std;

void function(int arr[], int size, int n){

    cout << "Results:\n";
    for (int i = 0; i<size; i++){
        if (arr[i] > n){
           cout << arr[i] << " ";
        }
    }
    cout << endl;
}

int main(){

    int arr[] = {23,7,9,41,4,5,18};
    int size = 7;
    int n;
    cout << "Given array is:\n";
    for (int i = 0; i<size; i++){
        cout << arr[i] << " ";
    }
    cout << endl;
    cout << "Enter n:";
    cin >> n;
    function(arr,size,n);  
}