Question

Write a C++ Program: Larger than n

In a program, write a function that accepts three arguments: an array, the size of the array, and a number n. Assume the array contains integers. The function should display all of the numbers in the array that are greater than the number n.

Test your function: a user should enter the size of the array, all elements of the array, and a number n.

Answer 1

#include<iostream>

using namespace std;

void largerThanN(int* arr, int size, int n){
   cout<<"\nLarger than "<<n<< " are:\n";
   for(int i = 0;i<size;i++){
      if(arr[i] > n)
         cout<<arr[i]<<endl;
   }
}

int main() {
   int n, size;
   
   cout<<"Enter size of an array: ";
   cin>>size;
   
   int* arr = new int[size];
   cout<<"Enter "<<size<<" integers for array:"<<endl;
   for(int i = 0;i<size;i++){
      cin>>arr[i];
   }
   
   cout<<"Enter value for n: ";
   cin>>n;
   
   largerThanN(arr, size, n);
   return 0;
}