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can someone answer C, I feel like im doing it correctly but keep gettting told my answer is wrong. thank you.

Calculate the maximum deceleration (in assume that the weight of the car is evenly )of a car that is heading down a 12.5 slop
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Answer #1

c)

acceleration along ramp

a = u g cos x - g sin x

a = 9.8* ( 0.1* sin 12.5 - sin 12.5)

a = - 1.164 m/s^2

Note: you can neglect negtive sign in orde rto have magnitude only

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Comment before rate in case any doubt, will reply for sure.. goodluck

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