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9. The goal is to find the electric field at the center of the semicircle below. There is a total charge equal to Q = +40 nC

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please rate it up!!! thanks!!!!a) 2 = Q = 40x100 = 254.770C/m 3.14x 5 b) ds=r de c) & E= f. kdor d Q = 2 de 22 Ey= 28 kads sino standa - 262 SR sinode :-22.

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