Question

2) Assuming the switch initially has been open for a really, really long time (a) obtain an expression for iw in the circuit which is valid for all t> 0; (b) calculate iw at t= 0 and t = 1.3 ns. 5 k12 10 k.22 5 1.5 V + m. 320 uH t= 0

Answer 1

Solution: 5 km Lok 2 REEC 1.5V 20 UH inductor for tro, circuit will be in steady state will be replace by shent circuit. 0569 10 KZ 1.5v 4 (0) 110) = 4:5 = 0.1mA AS ns ,10-) = 1,104) = 0.1 MA ) = 0.1 mA

for t>O; 20kn 054.2 1.5V ast → 10k2 5kr MAM i100) 1.5V © i (00) = O MA For equation of ill) įlt) = 100) + [.com) – į Coo) Tet/t. Calculatii 5k 10kr om Req. = 10kr /

To 20x106 10x103 -9 s dxtos 8xio Then equation of Ở 1:4) 0+ (0.13 € 4/28109 į tt) = 1. ¿lt) - 0.4 -0-5x16 + MA fom tr, o. for to At instant to 5K2 loka ion 5k2 1.5V@ iwko) ${1t) 1.5V wlt) iw10) = 1,5 1.5 - (lt) = - i, (t) {for to} = 0.3mA fou #= 1.3 xLoºs - 9 -0,5 X 10 X1. 3x10 int) = -0.1 € = -0.16 0.5X/03 = -0.18 0.65 ALL) = -0.05220 MA