Homework Answers
Labor content total=35+80+80+38=233 secs
Total idel time = 0+0+0+0 =0secs
Labot utilization = [233/(233+0)] *100 = 100%
N=2 the utilization will be 233/116.5 (Idle time becomes half)=200%
N=6 =37.4%
N=12 =23%
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Station B1 Run Time = 80 sec/unit C/O = 0 Station A Station C Run time...
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3. What is the labor content of a unit?
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