A)
given
wi = 0
a = 4 m/s^2
R = 100 mm = 0.1 m
angular acceleration of the pulley, alfa = a/r
= 4/0.1
= 40 rad/s^2
let t is the time taken for the hanging object to fall 1 m.
use, y = voy*t + (1/2)*a*t^2
y = 0 + (1/2)*a*t^2
==> t = sqrt(2*y/a)
= sqrt(2*1/4)
= 0.707 s
at t = 0.707 s,
w = wi + alfa*t
= 0 + 40*0.707
= 28.3 rad/s
B) Normal component of acceleration = R*w^2
= 0.1*28.3^2
= 80.1 m/s^2
oblem 173 0 and falls with a A starts from alt of 4 m/N mrmtproblemID-5609325 Part...
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