




20:51 43601_Assignm... QQ. 18% ; Question 1 CORRECTED [25 MARKS] Figure 1 shows a parallel chord...
Figure 1 shows a parallel chord truss of span 4 m and depth 3 m. Take E =200 kN/mm2. The solution follow the member labelling (1)- (17) as shown in the Figure) (7) tension members all have a cross-sectional area of 2000 mm2 and compression members have an area of 2500 mm2. Find the vertical deflection and horizontal deflection of the joint A. (In your (8) (14) (10) (12) (11) A (5) (4) (3) 4 PANELS @ 4 m =...
Question 1 (a) The truss of Figure 1 is subject to point loads at E and F and two members, 3 and 9, arriving on site 0.02 m too short. Use the Unit Load Theorem to find the vertical deflection at D. The product of area and Young's modulus, AE, for all members is 50,000 kN. (70%) 50 RN %3D 3m 4m Figure 1 లో ১a (b) If the answer to Part (a) is an upwards deflection at D of...
Member DB is pin connected at point B to the
beam ABC (figure 1)
Rahim Question 1 [25 MARKS] Using virtual work theory, find the vertical displacement at C due to a vertical point load of 20 KN acting downwards (1) at C in Figure 1. 5 m 20 kN B C A 3 m 5 m Figure 1
QUESTION 1 [25 marks A frame loaded with a uniformly distributed load at Member AB and point load at Member BC and joint B. It has pinned supports A and C, while joint B is fixed connected, as can be seen in Figure 1. Take E-200 GPa. a) Using the slope-deflection method, calculate the moments and illustrate the bending moment diagram. [15 marks) b) Then calculate the shear forces and sketch the shear force diagram. [10 marks) 22 KN 10...
This is statically indeterminate structure please solve using
Engesser's theorem.
8/9 (25 marks) Question 4 The elevations of all points on a parabolic arch (see Figure Q4a) are given by 4 h X - y = height of point above horizontal line joining springing points; rise; where span; horizontal distance of the point from a springing point W h k L Figure Q4a The horizontal reaction, H, at the support of a parabolic arch with point load, W, at a...
Question 4 The plane truss is subjected to a load as shown in Figure 4. Take E = 200 GPa and cross sectional areas of members 1, 2 and 3 as 150, 250 and 200 mm2 respectively a) Assemble the upper triangular part of the global stiffness matrix for the truss. b) Determine the horizontal and vertical displacements at node 4. c) Calculate the forces in each member of the truss. (25 marks) 20 kN 3 600 4 3 1.5m...
3. A two bar truss structure is shown in Figure 1. The coordinates of Points A, C and B are given by (0,0), (0, 10") and (10",0), respectively, in which the x-axis is from A to B and the y-axis is from A to C. Points A and C are fixed. The cross-sectional area of all members in inch?. A vertical point load, P, is applied at the tip of the structure, Point B. Based upon either the Principle of...
Figure Q5(a) shows a plane truss supported by a horizontal spring at the top node. The truss members are of a solid circular cross section having a diameter of 20 mm and an elastic modulus (E) of 80 GPa (10° N/m2). The spring has a stiffness constant of k-2000 kN/m. A point load of 15 kN is applied at the top node. The direction of the load is indicated in the figure. The code numbers for elements, nodes, DOFS, and...
QUESTION 2 [30 Marks) The framed structure shown in Figure 2 has simple supports (i.e. is free to rotate) at joints A and G. Members AC and GE are vertical, while CE and EH are horizontal. There is an internal moment release at joint C. A uniformly distributed load of 5 kN/m is applied between D and E, and another uniformly distributed load of 4 kN/m is applied between F and G as shown. There is also a horizontal point...
Question 1 (Total 100/3 Marks) Figure 1 (all units are mm) shows a simply supported beam of span 2500 mm with a 5 kN/m load. The cross-section of the beam is a composite section made from two steel plates attached to the top and bottom of a timber section. The top steel plate is 5 mm wide and 20 mm deep. The bottom steel plate is also 5 mm wide but 10 mm deep. The timber section is 50 mm...