Given two int values, return their sum. Unless the two values are the same, then return...
This CSIS 9 Python.
Java Python Warmup-2 > string_times prev next | chance Given a string and a non-negative int n, return a larger string that is n copies of the original string. string_times('Hi', 2) – 'HiHi' string_times('Hi', 3) - 'HiHiHi' string_times('Hi', 1) – 'Hi' Solution: Go Save, Compile, Run (ctrl-enter) Show Solution def string_times (str, n): def string_times(str, n): result = "" for i in range(n): # range(n) is [0, 1, 2, .... n-1] result = result + str...
in
python and according to this
#Creating class for stack
class My_Stack:
def __init__(self):
self.items = []
def isEmpty(self):
return self.items == []
def Push(self, d):
self.items.append(d)
def Pop(self):
return self.items.pop()
def Display(self):
for i in reversed(self.items):
print(i,end="")
print()
s = My_Stack()
#taking input from user
str = input('Enter your string for palindrome checking:
')
n= len(str)
#Pushing half of the string into stack
for i in range(int(n/2)):
s.Push(str[i])
print("S",end="")
s.Display()
s.Display()
#for the next half checking the upcoming string...
python function will Return True if string x contains 3 vowels in a row, in consecutive locations, false otherwise. assuming that 'vowels' refer to the following lowercase lttrs: a,e,i,o,u programs fails partially, only allowed to use float, str, int, appen, split, strip, len, range def vowels_three(x): for i in range (o, len(x), 2): if x[i] not in ('a,e,i,o,u'): return False return True
Given a string containing space-separated integer values, compute the sum of those values. Each string will contain at least one number. sumString("1 2") → 3 sumString("1 2 3") → 6 sumString("7 -7 0 59") → 59 int sumString(String str) { }
/** Given an int array, return true if the array contains duplicate values. duplicateInts({3}) -> false duplicateInts({1, 2}) -> false duplicateInts({7, 7}) -> true duplicateInts({1, 2, 3, 4, 5}) -> false duplicateInts({1, 2, 3, 2, 4, 5}) -> true **/ public static boolean duplicateInts(int[] numbers) { //your code here return false; }//end duplicateInts /** Given a String array, return true if the array contains duplicate values. Note: Capital letters count duplicateStrings({"a"}) -> false duplicateStrings({"a", "b", "c", "d"}) -> false duplicateStrings({"a",...
Python: problem 1 Given an array of integers, return the sum of two indices from this array based on input parameters, x and y. Example: Given nums = [2, 7, 11, 15], x = 3, y = 1 Because nums[x] + nums[y] = 15 + 7 = 22, return 22. You may use this as a template for your code class Solution: def two_sum(self, nums: List[int], x: int, y: int) -> int:
def calculate_total(price_list: List[list]) -> int: """Return the sum of all second elements in the sublists of price_list. Precondition: price_list is a list of lists of length 2, and the second element of it sublist is an int. >>> price_list = [["apple", 1], ["sugar", 5], ["mango", 3], ... ["coffee", 9], ["trail mix", 6]] >>> calculate_total(price_list)
Consider a non-empty int array ints. A contiguous subarray ints[ start .. start + len -1 ] (with starting index start and length len) is called a flat if all elements of that subarray are equal. Furthermore, such a subarray is called a plateau if it is flat and each of the elements ints[start -1] and ints[start + len] that immediately proceed/succeed the subarray are either nonexistent (i.e., out of array’s index range) or are strictly smaller than the elements...
I need assistance with this code. Is there any way I can create
this stack class (dealing with infix to postfix then postfix
evaluation) without utilizing <stdio.h> and
<math.h>?
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C++ Program:
#include <iostream>
#include <string>
#include <stdio.h>
#include <math.h>
using namespace std;
//Stack class
class STACK
{
private:
char *str;
int N;
public:
//Constructor
STACK(int maxN)
{
str = new char[maxN];
N = -1;
}
//Function that checks for empty
int empty()
{
return (N == -1);
}
//Push...
def slice_list(lst: List[Any], n: int) -> List[List[Any]]: """ Return a list containing slices of <lst> in order. Each slice is a list of size <n> containing the next <n> elements in <lst>. The last slice may contain fewer than <n> elements in order to make sure that the returned list contains all elements in <lst>. === Precondition === n <= len(lst) >>> slice_list([3, 4, 6, 2, 3], 2) == [[3, 4], [6, 2], [3]] True >>> slice_list(['a', 1, 6.0, False],...