Question

python

function will Return True if string x contains 3 vowels in a row, in consecutive locations, false otherwise. assuming that 'vowels' refer to the following lowercase lttrs: a,e,i,o,u

programs fails partially, only allowed to use float, str, int, appen, split, strip, len, range

def vowels_three(x):

for i in range (o, len(x), 2):

if x[i] not in ('a,e,i,o,u'):

return False

return True

Answer 1

def vowels_three(x):
        for i in range(0,len(x)-2): #we take 3 numbers at a time so, iterate over len(x)-3
                if (x[i] in ('a,e,i,o,u') and x[i+1] in ('a,e,i,o,u') and x[i+2] in ('a,e,i,o,u') ):
                        return True  #return true if all 3 elements are vowels 
        return False # return false when the loop ends, and no consecutive vowels found
print(vowels_three("abeiod")) #as an example take "abeiod". It must return true since "eio" are consecutive 3 vowels

I have taken "abeiod" as an example. You can take any example , the above code will run fine. since i have mentioned comments as well for your better understanding. you can use this code to test any cases and it will run fine.

The above code is also run fine for the string of length less than 3, since length is less than 3 , it must output False. which is done in the code as for loop will not execute because it will only run from 0 to len(x)-3. As range(0,x) will move from 0 to x-1, therefore our range function will move from 0 to len(x)-2-1= len(x)-3. and we check 3 characters x[i] , x[i+1] and x[i+2] for consecutive vowels . If all characters contain vowels, it will return true.

Thank You!