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   PYTHON --create a function that accepts a list of numbers and an int that returns...

  
PYTHON

--create a function that accepts a list of numbers and an int that returns index of 2nd occurrence of the int in list, otherwise returns None if # does not repeat more 2 or more times
EX: [10,24,3,45,10,49,4,5], 10) returns 4

--create a function that accepts a string that returns true if every letter of the alphabet can be found at least one time in the string, (has to be the lowercase alphabet), and false otherwise.
  

for BOTH you can ONLY use these functions --- append, len, str, float, range, strip, split, int


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Answer #1

1.

Source Code:

def firstRepeat(lst,num):
   count=0
   for i in range(0,len(lst)):
       if(lst[i]==num):
           count=count+1
       if(lst[i]==num and count==2):
          return i

print(firstRepeat([10,24,3,45,10,49,4,5],10))

main.py 1. def firstRepeat(lst, num): 2 count=0 3 for i in range(0, len(lst)): 4- if(lst[i]==num): 5 count=count+1 6 if(lst[i

2.

Source Code:

def isAll(string):
   isChar=False
   alpha=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
   for i in range(0,26):
       isChar=False
       for j in range(0,len(string)):
           if(alpha[i]==string[j]):
               isChar=True
       if(isChar==False):
           return False
   return True

print(isAll("abcdefghijklmnopqrstuvwxy")) # returns false because there is no 'z'
print(isAll("abcdefghijklmnopqrstuvwxyz")) # returns true

,x,y,z] main.py 1def isall(string): 2 isChar=False 3 alpha=[a,b,c,d, e 4 for i in range(0,26): 5 ischar=Fals

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