Question

Write a C program to show how many out of 500 are between 100 and 150.0. Hint: You need to implement a for loop to read each element of the array above. Use an if statement to specify the conditions and a counter to keep track of how many numbers were between 100 and 150.

2. A set of 500 float numbers is given below:
{133.077, 353.171, 272.317, 9.84711, 100.156, 468.909, 127.629, 1.25313, 331.166, 12.4806, 47.1308, 459.066, 222.106, 320.366, 447.939, 315.992, 368.533, 488.7, 316.918, 201.467, 61.2842, 356.199, 131.416, 110.222, 428.207, 4.02826, 359.1, 101.375, 329.052, 35.1193, 232.471, 101.122, 497.885, 23.6387, 186.34, 142.056, 276.78, 203.273, 238.401, 326.064, 408.247, 214.573, 421.483, 125.597, 347.963, 358.374, 291.067, 16.3751, 419.756, 355.345, 431.967, 415., 91.7042, 321.226, 200.497, 314.879, 93.8189, 298.587, 15.1569, 173.822, 317.039, 96.3144, 276.756, 347.759, 408.792, 381.742, 355.273, 223.162, 61.8293, 24.3681, 65.2061, 207.787, 142.073, 169.023, 133.239, 292.786, 51.3692, 347.797, 432.742, 477.908, 457.55, 50.2092, 418.585, 305.085, 141.511, 453.895, 142.829, 457.327, 232.719, 73.1532, 287.556, 235.165, 171.89, 49.7851, 223.35, 28.3785, 30.8162, 380.762, 91.111, 235.592, 479.447, 33.9658, 158.369, 257.684, 22.8966, 483.757, 239.784, 452.599, 381.386, 30.8617, 97.9551, 495.273, 149.667, 457.709, 310.399, 261.108, 477.777, 408.923, 88.0496, 233.729, 447.961, 29.1611, 496.939, 498.137, 468.514, 495.195, 339.569, 241.452, 446.617, 12.4387, 100.785, 288.853, 66.2314, 481.577, 3.83027, 293.581, 416.565, 24.8685, 193.431, 33.4731, 438.788, 115.945, 106.381, 299.744, 490.828, 87.784, 109.443, 301.607, 23.314, 92.5887, 269.873, 61.155, 76.6971, 81.15, 170.088, 272.302, 11.4657, 99.5729, 167.258, 478.721, 94.9008, 75.7044, 473.827, 446.248, 156.113, 459.759, 368.445, 147.504, 165.285, 372.975, 260.003, 345.897, 142.971, 281.387, 490.129, 285.742, 67.274, 201.237, 321.041, 14.4398, 56.8083, 102.664, 154.783, 35.7185, 461.908, 27.9593, 180.957, 89.4704, 306.795, 68.1999, 312.511, 441.966, 142.51, 195.225, 53.5086, 97.0697, 499.538, 413.838, 63.3795, 311.328, 433.264, 213.601, 242.338, 297.888, 377.456, 111.938, 88.5552, 263.17, 415.549, 84.9783, 407.599, 174.699, 109.754, 17.7784, 96.0876, 232.733, 467.244, 322.554, 43.579, 136.663, 467.706, 408.716, 480.199, 325.335, 35.4412, 196.114, 238.861, 28.4469, 157.985, 85.1769, 151.306, 265.277, 242.437, 1.19858, 243.707, 91.5778, 133.683, 483.42, 148.619, 358.845, 166.439, 161.866, 106.04, 223.182, 198.733, 253.151, 125.841, 397.846, 164.292, 58.0362, 386.98, 370.4, 7.30672, 472.859, 236.674, 106.122, 264.87, 472.661, 492.967, 15.5447, 132.187, 489.24, 345.348, 156.7, 465.749, 328.374, 240.307, 433.518, 268.016, 76.2234, 115.466, 36.6719, 104.724, 19.1872, 228.486, 166.272, 98.4171, 46.328, 491.812, 61.1499, 333.547, 73.6673, 498.844, 46.6052, 202.36, 84.4268, 154.496, 389.905, 236.611, 256.053, 414.189, 456.387, 468.595, 180.829, 299.723, 420.715, 364.871, 162.642, 72.2363, 255.443, 267.454, 117.314, 80.4245,

(a) Write a function, int factorial(int n), which returns n! (the factorial of n, i.e. 1 ×2 ×3 ××n.)
(b) Using int factorial(int n) above, write a program to compute

195.293, 433.907, 44.6469, 81.58, 149.688, 232.548, 460.22, 427.084, 259.782, 495.937, 205.167, 13.8946, 303.395, 28.3416, 25.3379, 214.172, 382.68, 163.47, 362.696, 142.936, 128.237, 396.016, 246.382, 63.5113, 432.945, 462.109, 202.735, 481.931, 284.257, 230.561, 242.515, 55.8477, 25.4743, 234.624, 38.3473, 42.9531, 222.079, 207.283, 14.0094, 328.781, 339.399, 44.8123, 151.314, 186.845, 212.161, 148.796, 404.932, 124.334, 279.217, 186.688, 203.197, 142.403, 494.96, 456.127, 460.683, 87.5551, 470.486, 222.503, 423.336, 45.602, 249.407, 16.22, 410.326, 216.821, 410.008, 471.408, 260.013, 30.9757, 198.847, 323.611, 355.081, 406.642, 419.63, 137.924, 152.883, 265.239, 424.67, 181.797, 192.2, 178.684, 454.185, 459.295, 268.865, 134.082, 205.778, 444.075, 358.539, 417.261, 295.77, 472.667, 99.5259, 387.285, 97.9232, 150.056, 244.445, 480.643, 178.293, 13.1318, 92.5622, 216.404, 253.623, 331.335, 400.362, 38.7207, 299.438, 372.04, 132.497, 404.639, 94.6604, 427.966, 273.959, 487.378, 298.89, 455.299, 175.433, 101.093, 201.967, 306.243, 430.987, 120.45, 24.6742, 294.111, 339.425, 404.045, 271.051, 462.777, 439.063, 366.325, 471.613, 91.7363, 307.566, 461.686, 377.953, 163.771, 34.6073, 474.307, 80.0622, 208.472, 359.175, 374.214, 378.095, 402.229, 428.187, 254.764, 354.421, 109.117, 89.762, 350.719, 84.3694, 146.341, 150.699, 484.394, 112.756, 55.6046, 343.133, 23.7084, 234.804, 391.834, 309.526, 49.4009, 155.742, 184.362, 450.351, 175.187, 277.647, 282.133, 23.1639, 420.422, 423.226, 174.016, 433.402, 70.7036, 339.857, 28.6748, 283.703, 86.3095, 228.1, 473.07, 440.57, 63.6011, 493.296, 82.2363, 132.045, 15.2001, 338.555, 397.874, 181.694, 340.013, 61.9079, 116.741, 159.53, 419.591, 138.682, 442.725, 226.128, 349.887, 298.825};

Answer 1

2. Code :

#include <stdio.h>

int main()
{
int count=0;   
float numbers[500];
for(int i=0;i<500;i++)  
{
scanf("%f",&numbers[i]);   
if(numbers[i]>100.0 && numbers[i]<150)  
{
count++;  
}
}
printf("The no. of elements between 100.0 and 150.0: %d",count);  
return 0;
}

Screenshot of the Code:

Midill. 1 include <stdio.h> int main() int count=0; // integer variable 'count' is initialized with e.. 'count' variable will keep track of total no(s) btw 100.0 & 150.0 float numbers [500); // float array 'numbers' is declared with size=500.. i.e., array numbers stores 500 elements for(int i=0;i<500;i++) Il for Loop block.. which starts from @ till 499 .. so for Loop block runs 499 times UBOVOU DW scanf("%f".&numbers[i]); // to read input entered by the user and stores in 'numbers il array! if(numbers[i]>100.0 && numbers[i]<156) // if statement to check each element of array is greater than 100.8 and less than 150.e! count++; // if condition is true .. then 'count' is incremented by 1 14 printf("The no. of elements between 100.0 and 150.0: %d", count); return 0; I Displays the total number of elements between 100 and 150.0,

OUTPUT:

349.887 298.825 The no. of elements between 100.0 and 150.0: 51 ... Program finished with exit code o Press ENTER to exit console. I

a) Code:

#include <stdio.h>
int fact(int n);

int fact(int n)   
{
if(n==0)   
{
return 1;
}
else   
{
return n*fact(n-1);   
}
}

int main()
{
int num,f;   
printf("Enter number: ");   
scanf("%d",&num);   
f=fact(num);   
printf("The factorial of num= %d",f);   
return 0;
}

Screenshot and Explanation of Code:

1 #include <stdio.h> 2 int fact(int n); // This function is invoked and int n=num 4 int fact(int n) 5-{ if(n==0) // if n equals to @ .. then return 1 because the factorial of 0 (0!) =1 return 1; 11 else // else { return n fact(n-1); // return (n* fact(n-1)) .. for ex: if n=2.. // then it is 2*fact(2-1) .. then 2*fact(1) invokes fact function again / so 'n' now equals to 1.. therefore .. return 2*1*fact(1-1) = 2*1*fact( // therefore 2*1*1 =2 is return to 'f' .. since fact@=1 17 } 18 19 int main() int num, f; // an integer variable num is declared.. whose factorial is to be calculated // also an integer var 'f' is declared printf("Enter number: "); // Displays message on the screen "Enter number" scanf("%d",&num); // scanf() reads user input and stores it in variable in 'num' f-fact(num); // used to invoke fact(int n) function and num is passed as parameter to the function fact(int n) // and the returned value is assigned to variable 'f' printf("The factorial of num= %d",f); // The factorial of num is Displayed return 0;

OUTPUT:

Enter number: 5 The factorial of num= 120 ... Program finished with exit code o