Question

Determine the final temperature. Express your answer using four significant fioures. A 1 g insulated aluminum cup at 18.66 C is fled with 138.6 g of water at 46.57 C. After a few is reached Submit Request Answer Part B Determine the total change in entropy ΑΣφ

Answer 1

Mass of the aluminum cup = 122.0 gm

Temp of Aluminum cup = 18.66 ⁰C

aluminum (specific heat capacity = 0.89 J °C^-1 g^-1)

Mass of the water = 138.6 gm

Temp of water = 46.57 ⁰C

Water (specific heat capacity = 4.184 J °C^-1 g^-1)

let the final temp of the system is T_f

_So

(mass Al) (Δt Al) (C_p Al) = (mass water) (Δt water) (C_p water)

(122) (T_f-18.66) (0.89) = (138.6) (46.57 -T_f) (4.184)

108.58T_f - 2026.1028 = 27006.054768.- 579.9024Tf

688.7524T_f = 29032.157568

T_f = 42.15 ⁰C

So the final temprature is 42.15 degree celcius

Entropy change is given by

S = mC_pLn(T2/T1)