A bar magnet is oriented with its magnetic dipole moment at 33.1° to the direction of a 0.0301-T magnetic field, causing a torque of 0.00213 N·m to act on it. Find the magnitude of the magnet\'s magnetic dipole moment.
torque = dipole moment X B ( cross porduct)
angle between dipole moment and B(magnetic field) is 33.1 degrees.
torque = mBsin33.1
0.00213 = m * 0.0301* sin33.1
m = 0.129 A.m^2
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a bar magnet of magnetic moment 6 J/T is aligned at 60 degree
with a uniform external magnetic field of 0.44 T. Calculate (a) the
work done in turning the magnet to align its magnetic moment (1)
normal to the magnetic fiel
A bar magnet of magnetic moment 6 J/T is aligned at 60° with a uniform external magnetic field of 0-44 T. Calculate (a) the work done in turning the magnet to align its magnetic moment (i) normal to...
1. Magnetic field (B) exerts a torque on a magnetic moment (m)
(such as a magnet bar) to align the magnetic moment along the B-
field direction. In genreal, the vector torque is defined as:
t=mxB, with a magnitude of
, where
is the angle between m and B as shown in figure 1. However, in Eq.
(1) the magnitude of t is defined as
. What does the minus sign mean?
T = ITI = mBsinΘ
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