Question

Exercise 04: Tool Solte calcular: TI - a) The total impedance of the core AB in rectangular and polar forms IuF 6 The current of the ene Ab in polar form. C) The current through the capacitor d) The Phaso diagram showing voltage source and all currents with the phase differences. ми Dell Exercise

Answer 1

___ @ Total_mpedance of cooil AB- 2l = 10+7WL = 10 + 200 L =10+(2x3.14 x 50 x 33x103) => 24 = (10 +j10-36) 3 (Rectangular form) reagoitude of 21 = ZL=1&+40:36)2 = 14.405 Phase angle, 0 = tamil 1036) = 46-01 = 14.40 (46-01" (A frolas form) 14.40_12 O current in Coil AB Ian = Voltage 100 4.40/46-01 1 InB = 6.944-46.01° A © impedance offered by Capacitor- Zc = jwc current through the capacitor- Ic = V = 100 = 100x jwe - Zc Ljux) = Ic = À 100x (2x3-14X50) x 180x1o-t

[Ic = 35.65 A = Ic = 5.65 /9º A 90° a) Khi te higo V46.012 1:180° TAB - - 270 Phase angle o IAB is so it is drawn below the negative of 46001 - o line ..