Question

hi, this is settling an argument so please get it right:)

QUESTION 3 (20 marks) Draw the shear and moment diagrams for the following beam. 2 kN/m 2 kN/m 18 kNm 3 m3 m 6 kN

Answer 1

solution:

Solution :- 2KN/m 2KNIM 6KN 3m — * 3m - GKN SED 12 KNMI 8 MD 2 (3-2) 2KN/m i In BC (a from c) Sn = (2+ 2/3 (3-2)] BK3- 12 At azo, sc = 1/2 X (2+2) A+1 = 3m, SBS 1/2 x2x3 = 3kN

Ma = ( 213(3-1) + 2] x [4+ 213 (3-2)] 2+2/3 (3-2) At a=0 Mc = - 1 (2+2)x0= 0 kNm At x=3m, MB=-1/2 x 2 x 33 x 3x (4*0 ato = -6kN-m i In AB & from B 2 kN/m 2kN/m Sa = 1x2x3 + ₂2x2x2/2 2/1 At x=0, SB = 3 KN A ka * 3m At 2=6m, SA= 3+3=6KN Ma - 1/2 X3 X2 ( 2 + 2/3X3) + (-1/2x2x2/32 * 2/3) At a=0 MB = - 6kN-m At 1=3m, MA - -1/2 x 3X2 X (5) + (-42) X3x2/3x3x3/2 - 18 KNM Summary :- 1. he convex and concave shape in the SFD is decided by the load application

The first denivative of the sf equation at any point gives the loading detail at that point → The load is hon zero at A and c but load at Bis zero that leads to the change in slope. in SFD 2. The first derivative of BMD at any point gives the SFO value at that point. so the curve is concave with slope zero point c because sf is zero at c. at