Question

An object 0.600 cm tall is placed 18.0 cm to the left of the vertex of a concave spherical mirror having a radius of curvature of 21.5 cm. Calculate the position of the image. Calculate the size of the image. Find the orientation (upright or inverted) and the nature (real or virtual) of the image.

Answer 1

KR=2150 JA 4 Loo C K 18.00m (u) Here Radius of curvature R = 21.5cm Let B be the object position - AB = 18.0 con cu let) Af is the focal length. eta - 21.5 - 10.75 cm The object is between focus f and center of curvature c. het & be the a smage distance toutes Here u – 18.0 cm. f = – 10.75 con. la'sign indicates direction.

to t-ta Howrs - tre - to.75 + 7/8 -10.75 - 18.0 to = -0.04 - 26.6.9 cm The image will be formed 26.69cm to the left of the vertes of a concave spherical mirror, We know, Lateral magnification im height of the image I height of the object o and also m = - image distance object distance Í -- 91492. I. vxo - -26.69 2 x 0.600 cm - 18.0 =-0.89 cm

The size of the image = 0.89 cm re image is formed the left side from the vertex and object also placed in the & left side of the verten. So, the mal-ve' So, the image is real image. and here I is a negative, so, the image inverted.