i got to the end but couldnt find the right value for R. and
explanation would be appreciated.i got to the end but couldnt find the right value for R. and explanation would...
A satellite is in a circular orbit about the Earth at a distance of four (4) Earth radii above the surface of the Earth. What is the velocity of the satellite? (Earth's mass: ME = 5.98 x 1024 kg; the radius of the Earth: 6.4 x 106m ; G = 6.67 x 10-11 Nm2/kg2 ). A) 4,072.5 m/s B)3,530.5 m/s C)5,582.2 m/s D)7,465.9 m/s
A satellite used in a cellular telephone network has a mass of 2380 kg and is in a circular orbit at a height of 850 km above the surface of the earth. Part A What is the gravitational force Fgrav on the satellite? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m
A satellite m = 500 kg orbits the earth at a distance d = 218 km, above the surface of the planet. The radius of the earth is re = 6.38 × 106 m and the gravitational constant G = 6.67 × 10-11 N m2/kg2 and the Earth's mass is me = 5.98 × 1024 kg. What is the speed of the satellite in m/s?
A satellite used in a cellular telephone network has a mass of 2050 kg and is in a circular orbit at a height of 880 km above the surface of the earth. Part A What is the gravitational force Fgrav on the satellite? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m . part...
please help!
(1 point) How much work is required to lift a 1500-kg satellite to an altitude of 1.100 m above the surface of the Earth? The gravitational force is F=GMm/r2, where M is the mass of the Earth, m is the mass of the satellite, and is the distance between the satellite and the Earth's center. The radius of the Earth is 6.4. 100 m, its mass is 6 . 1024 kg, and in these units the gravitational constant,...
Consider a 495 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 103 km and Me = 5.97 x 1024 kg,...
a 83.5 kg satellite has a perigee of 6.61 x 10^6m and a apogee
of 7.33 x 10^6m. What is the difference in gravitational potential
energy as it moves from perigee to apogee.
9. An 83.5-kg satellite has a perigee (the distance from the point of closest approach to the T center of the Earth) of 6.61 *10 m and an apogee (the distance from the furthest point in the orbit to the center of the Earth) of 7.33 x...
A 507 kg satellite is in a circular orbit at an altitude of 754 km above a planet’s surface. This planet is similar to our Earth. Because of air friction, the satellite eventually is brought to the Earth’s surface, and it hits the Earth with a speed of 3 km/s. The radius of the planet is 7 × 106 m and its mass is 8 × 1024 kg. The gravitational constant is 6.67259 × 10−11 N m2 /kg2. How much...
A satellite of mass 350 kg is launched from a site on the Equator into an orbit at 317 km above Earth’s surface. If the orbit is circular, what is the satellite’s speed in orbit? The gravitational constant is 6.67259 × 10−11 N · m2 /kg2 , the mass of the earth is 5.98 × 1024 kg and its radius is 6.37 × 106 m . Answer in units of m/s. 018 (part 2 of 3) 10.0 points What is...
Consider a 475 kg satellite in a circular orbit at a distance of 3.06 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 109 km and Me = 5.97 x 1024 kg,...