Question

A survey of 300 students is selected randomly on a large university campus. They are asked if they usea laptop in class to take notes. Suppose that based on the survey, 135 of the 300 students responded "yes." a) What is the value of the sample proportion p? b) What is the standard error of the sample proportion? c) Construct an approximate 95% confidence interval for the true proportion p by taking 2 SEs from the sample proportion. a) p 0.45 (Type an integer or a decimal.) b) The standard error of the sample proportion is 0.029 (Round to three decimal places as needed.) c) The approximate 95% confidence interval for the true proportion p by taking proportion is ( 2 SEs from the sample (Round to three decimal places as needed.)

Answer 1

c)

p = 0.45

SE = 0.029

So,

{0.45 - 2 * 0.029, 0.45 + 2 * 0.029}

Thus,

{0.393, 0.508}

Thus,

interval is

{0.393, 0.508}