In a survey of 385 students at Broward College, North Campus, results revealed that 154 students...
- In a survey of 385 students at Broward College, North Campus, results revealed that 154 students were born outside of the USA. Construct a 96% confidence interval estimate for the proportion of students who were born outside the USA. Show your calculations on a separate sheet of paper for p-hat. Q-hat, the margin of error and the construction of the confidence interval. Also, give your interpretation of the confidence interval estimate. SHOW WORK
Homework Answers
Sample proportion 
= 154 / 385
= 0.40
= 1 -
= 1 - 0.4 =
0.6
Margin of error = Z
/2 * sqrt(
* / n)
= 2.0537 * sqrt( 0.4 * 0.6 / 385)
= 0.0513
96% Confidence interva for p is
- ME < p
< + ME
0.4 - 0.0513 < p < 0.4 + 0.0513
0.379 < p < 0.451
96% CI is ( 0.379 , 0.451)
Interpretation - we are 96% confident that the proportion of students who born outside the USA is
between 0.379 and 0.451.
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In a survey of 385 students at Broward College, North Campus,
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