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Computer Science, Physics and Engineering Q5: [ 20 points). For the network in Fig. 5: a. Find the Thévenin equivalent circui
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Q5. Given metwork, Ri 6n2 * of Exis Ryn (a) Pino- For B short the open the E voltage source. current source) pif present .current through Rizur is zero. so, voltage across R2=31 is th, since they are in Parallel. RyZ VR, 2 na Ex Ritha 18x a = 6V 6power when (6) Manimem power Transfer s i ... The resistor R will receive manimum . R = Rth [Thevenins resistance from la),By manimum power Transfer theorem, Prnan - Viht = (6) ² = 36 = 1.5hl . 4 Path Pmai= 1.5h 4X6 Vh=6V Rih=62 Pman = 1.56

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