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10. Two uncharged metal ball, X and Y, stand on glass rods. A third ball Z carrying a positive charge, is brought near ball Y. A conducting wire is then run between X and Y. The wire is then removed, and ball 2 is taken away. When this is all done what will be the sign of the charges on balls x and Y? Explain your reasoning
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When the charged ball is brought near, the two neutral balls will be polarized slightly because of the electric field that is set up by ball Z. What that means is that the -ve charges in the neutral balls are attracted to the +ve charge of Z, the +ve charges are repelled. When the wire is connected, some electrons will flow from X to Y. You can look at it as one object now, where the -ve charges are trying to get even closer on the whole to the +ve of Z. When the wire is then disconnected, the charges stay divided, so X will have +ve charge and Y will have -ve charge.

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