Question

Check the youn g book for emple 010 02 OOO 04110/10 Grade O Type here to search

Answer 1

Part A)-

As per given data-

The magnitude of force $\propto$ speed² and We know that F = ma than-

| F| = Kv² where K = proportion constant and F = ma

ma = Kv² and we know that a=dv/dt so,

m*(dv/dt) = Kv²

m(dv/dt) - Kv² = 0 .... (1) differential euqation

Part B)-

if we solve this differential eqn further -

and we will cross-multiplication here-

m(dv /v²) = K*dt

If we take intigration both the sides than-

m (v^-1/-1) = K*t

1/v = - (K/m)*t velocity in function of time.

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