
6. Teeny, the 3,750 kg ice skating elephant, begins a spin with an angular speed of...
A 60.0-kg skater begins a spin with an angular speed of 6.0 rad/s and of moment of inertia 3.0 kg.m2. By changing the position of her arms, the skater decreases her moment of inertia to one-half its initial value. What is the skater's initial kinetic energy?
As an ice skater begins a spin, his angular speed is 3.37 rad/s. After pulling in his arms, his angular speed increases to 5.74 rad/s. A)Find the ratio of the skater's final moment of inertia to his initial moment of inertia.
2. As Wile E continues giving chase, he finds himself skating on ice. As the road runner whooshes past him, he spins with an angular speed of 12.0 rad/s. By opening up his arms, Wile E. increases his moment of inertia to double its initial value. What is Wile E.’s final angular speed? Please Show All Work
1. An ice skater spins on the ice with her arms positioned tight against her body. In this position, she has a moment of inertia of 1.3 kg m2 and an angular speed of 15 rad/s. If the ice skater then stretches out her arms, and her angular speed slows to 6.0 rad/s, what is her moment of inertia with her arms outstretched? 3.64 kg m2 4.91 kg m2 3.25 kg.m2 4.39 kg m2 6.11 kg m2 А В С...
An ice skater spins, with her arms and one leg outstretched, and achieves an angular velocity of 2 rad/s. when she pulls in her arms, her moment of inertia decreases to 65% its original value. what is her new angular velocity?
4. An ice skater with rotational inertia I = 0.23 kg*m* is spinning with angular speed w. They pull their arms in, increasing their angular speed to 4w. What is the final moment of inertia?
You will estimate how much slower an ice skater would spin, if a can of soda dropped into her hand while she was spinning. You may model her body as a vertical cylinder of radius 20 cm and mass of 50 kg, spinning about a vertical axis. Assume that she's initally spinning 10 times per second, so that initially wi=20 (pi)s-1. Suddenly she is handed the soda can, which is small enough that we can model it as a point-like...
Calculate the angular momentum, in kg · m2/s, of an ice skater
spinning at 6.00 rev/s given his moment of inertia is 0.330 kg ·
m2.
(a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
(a) Calculate the angular momentum (in kg-m/s) of an ice skater spinning at 6.00 rav/s given his moment of inertia is 0.470 kg m? kg-m/s (b) He reduces his rate of spin (his angular velocity) by extending wis arms and increasing his moment of inertia Find the value of his moment of inertia (in kg) ir his angular velocity drops to 2.05 rev/s. kgim² (c) Suppose instead he keeps his arms in and allows friction with the ice to slow...
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?