A 93.0-mH inductor and a
6.50-μF capacitor are connected in series with a generator whose
frequency is 549 Hz. The rms voltage across the capacitor is 2.50
V. Determine the rms voltage across the inductor.
Homework Answers
xL = 2*3.14*f*L
= 2*3.14*549*93*10^-3
= 320.6 ohm
xC = 1/(2*3.14*f*C)
= 1/(2*3.14*549*6.50*10^-6)
= 1/(22.4*10^-3)
= 44.6 ohm
given,
vC = Irms*xC
2.5 = Irms*44.6
Irms = 0.0561 Amp
vL = Irms*xL
= 0.0561*320.6
= 18.0 V
Answer: 18.0 V
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