Question

Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select 'l' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 1.1 g of potassium acetate (KCH3CO2) dissolved in 300. mL of water (choose one) (choose one) 1.1 g of propylene glycol (C3H2O2) dissolved in 300. mL of water (choose one) (choose one) 1.1 g of hydrochloric acid (HCI) dissolved in 300. mL of water (choose one) (choose one) 300. mL of pure water (choose one) : (choose one) x 6 ?

Answer 1

í Allution b. Mass of solvent water in leg= 300 | Molar mass I avenmass / No. of moles I molality (m) l 1 98.15 Gott 0-0112 retro -0382 testy = 0.01445 30VHAS = 0.045 3615 3615 +0-030135.03- 0-1042 Sentine) C3 HgO, 7691 1. / Hce otbo=ikbm AT6 = 2XKG X0-0373 = 0.0746 kb - ATS (k = i Kfm for Keh, co, solution - 04, = 2x K4*0.0343 P - 0.0746 Kg for CG HgO2 Otse = 1x K4* 0-048 -0.048Kq for He ATE = 2x K4*0-1004 - 0.2008 K+ OTD2 = IXKpX0.048 = 0.048 Kb ATD, 2XK1X01004 = 0.2008 Kb freezing paint Pure water : Tf Toca . 10.048nf 10.674bly C3H5OZ solu" - C3H₂O₂ solu" totsla K CH CO, solu" - Ots --- cs Scanned withhu 103 - - - - - CamScanner

ни доим Јо. 208 К Кщо, зол" \0-2998 Jo-o19 CHgo, T О-очек, | Pure watu k ot 100°c freezing paint Boiling pant Кои, ю, C3 HQ O, Ни - saw Water Scanned with CamScanner
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