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In the laboratory you dissolve 12.6 g of manganese(II) chloride in a volumetric flask and add water to a total volume of 125
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Answer #1

Molar mass of manganese choti de=125.844 g/mol.

1000 mL 125.844 g=1 M solution

125 mL 12.6 g=0.8 M

1000 mL 1 M=125.844 g

125 mL 1 M=125.844×125/1000=15.73 g

15.73 g=1M

12.6g=12.6/15.73=0.8 M

1 mole MnCl2 produces 1 mole Mn2+ and 2 moles of Cl-.

Molarity of manganese cation=0.8 M

Concentration of chloride=0.8×2=1.6 M

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