Question

Fil in each labels on the diagram of a galvanic cell below based on the following reaction and then determine the Eof the cell. Sn2+(aq) + Al(s) —Sn(s) + Aj 3+(aq) F D With respect to the metal is Select 1 and it is the Select With respect to the metalis Select 1 and it is the Select With respect to the solution is Select ! With respect to the solution is Select 1 With respect to this is called the Select With respect to F. there is usually a Select to measure the current The Eof the cellis Select v volts

for sentence 1 and 2 these are the options (respect to a and b.

for sentnece 3 and 4 these are the options (with respect to c and d

for sentence 5 (witg respect to E)

for sentence 6 (with respect to F)

for sentence 7 (the E degree of the cell)

THANK YOU

Answer 1

Question	Answer	Explanation
With respect to A the metal is	Al and it is Anode	Left hand side eletrode is anode and it will undergo oxidation.
With respect to B the metal is	Sn and it is Cathode	Right hand side eletrode is cathode and it will undergo reduction
With respect to C the solution is	Al3+	Because the anode is Al dipped in its own salt
With respect to D the solution is	Sn2+	Because the cathode is Sn dipped in its own salt
With respect to E is called	Salt bridge	Salt bridge is directly connected to the two solutions without any wire as medium.
With respect to F there is usually---- to measure the current.	Voltmeter	Since the cell is galvanic cell, it will generate current in Volts. It has to be measured by Voltmeter. Also, a hint is given:"to measure the current". A galvanic cell is otherwise called as Voltaic cell
E0 of the cell	+1.522 V	E0Al3+/Al = -1.662V E0Sn2+/Sn = -0.14 V Ecell = ER -EL         = -0.14 -(-1.662)         = -0.14 + 1.662         = 1.522 V